College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 70

Answer

The Width of the room is $12ft$

Work Step by Step

$\underline{\textbf{Givens:}}$ $Area=228ft2$ $Width=x$ $Length(L)=x+7ft$ $We know Area of a Rectangle =L\times W$ i.e $x(x+7)=228$ $\Rightarrow x^2+7x=228$ $\Rightarrow x^2+7x-228=0$ By Factoring $\Rightarrow (x-12)(x+19)=0$ $\Rightarrow x=12$ or $x=-19\hspace{0.3cm} {\color{red}{Rejected}}$ Width can not be expressed with a negative measurement. $Width = 12ft$ $Length= 12+7=19ft$
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