## College Algebra 7th Edition

$x=0.9$
We use the quadratic formula: $x^{2}-1.800x+0.810=0$ $x=\displaystyle \frac{-(-1.8)\pm\sqrt{(-1.8)^{2}-4(1)(0.81)}}{2(1)}=\frac{1.8\pm\sqrt{3.24-3.24}}{2}=\frac{1.8\pm\sqrt{0}}{2}=\frac{1.8}{2}=0.9$