College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises: 50

Answer

$x=0.9$

Work Step by Step

We use the quadratic formula: $x^{2}-1.800x+0.810=0$ $x=\displaystyle \frac{-(-1.8)\pm\sqrt{(-1.8)^{2}-4(1)(0.81)}}{2(1)}=\frac{1.8\pm\sqrt{3.24-3.24}}{2}=\frac{1.8\pm\sqrt{0}}{2}=\frac{1.8}{2}=0.9$
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