College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises: 40

Answer

$2\pm\sqrt{3}$

Work Step by Step

We solve using the quadratic formula: $0=x^{2}-4x+1$ $x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{-(-4)\pm\sqrt{(-4)^{2}-4(1)(1)}}{2(1)}=\frac{4\pm\sqrt{16-4}}{2}=\frac{4\pm\sqrt{12}}{2}=\frac{4\pm\sqrt{4*3}}{2}=\frac{4\pm 2\sqrt{3}}{2}=2\pm\sqrt{3}$
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