Answer
$2\pm\sqrt{3}$
Work Step by Step
We solve using the quadratic formula:
$0=x^{2}-4x+1$
$x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{-(-4)\pm\sqrt{(-4)^{2}-4(1)(1)}}{2(1)}=\frac{4\pm\sqrt{16-4}}{2}=\frac{4\pm\sqrt{12}}{2}=\frac{4\pm\sqrt{4*3}}{2}=\frac{4\pm 2\sqrt{3}}{2}=2\pm\sqrt{3}$
