College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 7

Answer

$P(6,2)=30$

Work Step by Step

Use the permutation formula to obtain $P(n,r)=\frac{n!}{(n-r)!}$ $P(6,2)=\frac{6!}{(6-2)!}=\frac{6!}{4!}=\frac{6\cdot5\cdot4!}{4!}=30$
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