College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding: 15

Answer

$C(8,2)=28$

Work Step by Step

Using the combination formula, we obtain: $C(n,r)=\frac{n!}{(n-r)!r!}$ $C(8,2)=\frac{8!}{(8-2)!2!}=\frac{8!}{6!2!}=\frac{8\cdot7\cdot6!}{6!\cdot2\cdot1}=28$
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