College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 16

Answer

$C(8,6)=28$

Work Step by Step

Use the combination formula, we obtain: $C(n,r)=\frac{n!}{(n-r)!r!}$ $C(8,6)=\frac{8!}{(8-6)!6!}=\frac{8!}{2!6!}=\frac{8\cdot7\cdot6!}{2\cdot1\cdot6!}=28$
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