Answer
$336$
Work Step by Step
Suppose there are two groups with $n$ and $m$ objects. If we form a group choosing $r(r\leq n)$ and $s (s \leq m)$ objects from these two groups respectively and order doesn't matter, then there are $C(n, r) \times C(m, s)$ ways of forming such a group.
$C(4,2) \times C(8,3) = 6 \times 56 = 336$
