College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 46

Answer

a) $6,760,000$ b) $3,407,040$ c) $3,276,000$

Work Step by Step

Note that there is 26 letters and 10 digits a) $26\times26\times10\times10\times10\times10=6,760,000$ The numbers stay at 26 and 10 because the letters and digits may be repeated b) $26\times26\times10\times9\times8\times7=3,407,040$ The 26 stays constant but the 10 decreases because the digits can not be repeated c) $26\times25\times10\times9\times8\times7=3,276,000$ Both the 26 and 10 decrease because the letters and digits cannot be repeated
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