Answer
$24$
Work Step by Step
The number of ways to arrange $n$ objects, all of which are different, is $n!$.
$4! = 4 \times 3 \times 2 \times 1 = 24$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 35
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