College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding: 19

Answer

$C(15,15)=1$

Work Step by Step

Using the combination formula, we obtain: $C(n,r)=\frac{n!}{(n-r)!r!}$ $C(15,15)=\frac{15!}{(15-15)!15!}=\frac{15!}{0!15!}=\frac{15!}{15!\cdot1}=1$
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