College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.2 - Permutations and Combinations - 10.2 Assess Your Understanding - Page 695: 48

Answer

$6,302,555,018,760$

Work Step by Step

There are $365$ choices for the first birthday, $364$ choices for the second birthday, $363$ choices for the third birthday, $362$ choices for the fourth birthday, $361$ choices for the fifth birthday. Therefore, $365 \times 364 \times 363 \times 362 \times 361 = 6, 302, 555, 018, 760$
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