College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding: 36

Answer

The solution set is {$-2,0$}

Work Step by Step

$|x^2-2x|=|x^2+6x|$ $x^2-2x=x^2+6x$ or $x^2-2x=-1(x^2+6x)$ $x^2-2x-x^2-6x=0$ or $x^2-2x+x^2+6x=0$ $-8x=0$ or $2x^2+4x=0$ $x=0$ or $2x(x+2)=0$ $x=0$ or $2x=0$ or $x+2=0$ $x=0$ or $x=0$ or $x=-2$ The solution set is {$-2,0$}
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