Answer
$(-\infty,-3/2)\cup(3/2,\infty)$
Work Step by Step
$|-2x|\gt|-3|$, so
$|2x|\gt3$, so
$|x|\gt3/2$, so
$x\gt3/2$ or $x\lt-3/2$, thus the solution set is $(-\infty,-3/2)\cup(3/2,\infty)$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 53
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