Answer
$(-\infty,-1)\cup(2,\infty)$
Work Step by Step
$|1-2x|\gt3$, so $1-2x\gt3$ or $1-2x\lt-3$,
so $-2x\gt2$ or $-2x\lt-4$,
so $x\lt-1$ or $x\gt2$ thus the solution set is $(-\infty,-1)\cup(2,\infty)$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 49
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