College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding: 43

Answer

The solution is $[-\frac{2}{3},2]$.

Work Step by Step

$|3t-2|\leq4$ Isolate the absolute value $-4\le3t-2\leq4$ Add 2 to each term $-4+2\le3t-2+2\leq4+2$ $-2\leq3t\leq6$ Divide each term by 3 $\frac{-2}{3}\leq\frac{3t}{3}\leq\frac{6}{3}$ $-\frac{2}{3}\leq{t}\leq2$ The solution is $[-\frac{2}{3},2]$.
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