Answer
The solution is $[-\frac{2}{3},2]$.
Work Step by Step
$|3t-2|\leq4$ Isolate the absolute value
$-4\le3t-2\leq4$ Add 2 to each term
$-4+2\le3t-2+2\leq4+2$
$-2\leq3t\leq6$ Divide each term by 3
$\frac{-2}{3}\leq\frac{3t}{3}\leq\frac{6}{3}$
$-\frac{2}{3}\leq{t}\leq2$
The solution is $[-\frac{2}{3},2]$.
