Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 32

The real solution set is {-4,-3,0,1}.

$|x^2+3x-2|=2$ $x^2+3x-2=2$ or $x^2+3x-2=-2$ $x^2+3x-2-2=0$ or $x^2+3x-2+2=0$ $x^2+3x-4=0$ or $x^2+3x=0$ $(x+4)(x-1)=0$ or $x(x+3)=0$ $x+4=0$ or $x-1=0$ or $x =0 $ or $x+3=0$ $x=-4 $ or $x=1$ or $x=0 $ or $x=-3$ The real solution set is {-4,-3,0,1}.