Answer
The solution is $[-6,1]$.
Work Step by Step
$|2u+5|\leq7$ Isolate the absolute value
$-7\le2u+5\leq7$ Add 2 to each term
$-7-5\le2u+5-5\leq7-5$
$-12\leq2u\leq2$ Divide each term by 3
$\frac{-12}{2}\leq\frac{2u}{2}\leq\frac{2}{2}$
$-6\leq{u}\leq1$
The solution is $[-6,1]$.
