Answer
The solution set is {$-\frac{4}{3},\frac{8}{3}$}
Work Step by Step
$|\frac{x}{2}-\frac{1}{3}|=1$
$\frac{x}{2}-\frac{1}{3}=1$ or $\frac{x}{2}-\frac{1}
{3}=-1$
$\frac{x}{2}=1+\frac{1}{3}$ or $\frac{x}{2}=-1+\frac{1}
{3}$
$\frac{x}{2}=\frac{3+1}{3}$ or $\frac{x}{2}=\frac{-3+1}{3}$
$\frac{x}{2}=\frac{4}{3}$ or $\frac{x}{2}=-\frac{2}{3}$
$x=\frac{4}{3}\cdot2$ or $x=-\frac{2}{3}\cdot2$
$x=\frac{8}{3}$ or $x=-\frac{4}{3}$
The solution set is {$-\frac{4}{3},\frac{8}{3}$}
