Answer
The solution set is{ $-\frac{27}{2},\frac{27}{2}$}.
Work Step by Step
$\frac{2}{3}|x|=9$ Isolate the absolute value by making the coefficient of$ |x|$ one.
$|x|=9\cdot\frac{3}{2}$
$|x|=\frac{27}{2}$
$x=\frac{27}{2}$ or $x=-\frac{27}{2}$
The solution set is{ $-\frac{27}{2},\frac{27}{2}$}.