Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set: 9

Answer

$\dfrac{6x+6}{5}\cdot\dfrac{10}{36x+36}=\dfrac{1}{3}$

Work Step by Step

$\dfrac{6x+6}{5}\cdot\dfrac{10}{36x+36}$ Factor the numerator of the first fraction by taking out common factor $6$: $\dfrac{6x+6}{5}\cdot\dfrac{10}{36x+36}=\dfrac{6(x+1)}{5}\cdot\dfrac{10}{36x+36}=...$ Factor the denominator of the second fraction by taking out common factor $36$: $...=\dfrac{6(x+1)}{5}\cdot\dfrac{10}{36(x+1)}=...$ Multiply the two rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{60(x+1)}{180(x+1)}=\dfrac{60}{180}=\dfrac{1}{3}$
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