Answer
$\dfrac{6x+6}{5}\cdot\dfrac{10}{36x+36}=\dfrac{1}{3}$
Work Step by Step
$\dfrac{6x+6}{5}\cdot\dfrac{10}{36x+36}$
Factor the numerator of the first fraction by taking out common factor $6$:
$\dfrac{6x+6}{5}\cdot\dfrac{10}{36x+36}=\dfrac{6(x+1)}{5}\cdot\dfrac{10}{36x+36}=...$
Factor the denominator of the second fraction by taking out common factor $36$:
$...=\dfrac{6(x+1)}{5}\cdot\dfrac{10}{36(x+1)}=...$
Multiply the two rational expressions and simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{60(x+1)}{180(x+1)}=\dfrac{60}{180}=\dfrac{1}{3}$
