Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 499: 5

Answer

$-\dfrac{5a^{2}b}{30a^{2}b^{2}}\cdot b^{3}=-\dfrac{b^{2}}{6}$

Work Step by Step

$-\dfrac{5a^{2}b}{30a^{2}b^{2}}\cdot b^{3}$ Multiply both expressions and simplify by removing repeated factors in the numerator and the denominator: $-\dfrac{5a^{2}b}{30a^{2}b^{2}}\cdot b^{3}=-\dfrac{5a^{2}b^{4}}{30a^{2}b^{2}}=-\dfrac{5b^{2}}{30}=-\dfrac{b^{2}}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.