Answer
$\dfrac{x^{2}+x}{8}\cdot\dfrac{16}{x+1}=2x$
Work Step by Step
$\dfrac{x^{2}+x}{8}\cdot\dfrac{16}{x+1}$
Factor the numerator of the first fraction by taking out common factor $x$:
$\dfrac{x^{2}+x}{8}\cdot\dfrac{16}{x+1}=\dfrac{x(x+1)}{8}\cdot\dfrac{16}{x+1}=...$
Multiply the two rational expressions and simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{16x(x+1)}{8(x+1)}=\dfrac{16x}{8}=2x$
