Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set: 22

Answer

$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}=x+3$

Work Step by Step

$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}$ Take out common factor $5$ from the numerator of the second fraction: $\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}=\dfrac{(x+3)^{2}}{5}\div\dfrac{5(x+3)}{25}=...$ Evaluate the division of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{25(x+3)^{2}}{25(x+3)}=x+3$
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