Answer
$\dfrac{7a^{2}b}{3ab^{2}}\div\dfrac{21a^{2}b^{2}}{14ab}=\dfrac{14}{9b^{2}}$
Work Step by Step
$\dfrac{7a^{2}b}{3ab^{2}}\div\dfrac{21a^{2}b^{2}}{14ab}$
Divide the two rational expressions:
$\dfrac{7a^{2}b}{3ab^{2}}\div\dfrac{21a^{2}b^{2}}{14ab}=\dfrac{(7a^{2}b)(14ab)}{(3ab^{2})(21a^{2}b^{2})}=\dfrac{98a^{3}b^{2}}{63a^{3}b^{4}}=...$
Simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{98}{63b^{2}}=\dfrac{14}{9b^{2}}$
