Answer
$-\dfrac{9x^{3}y^{2}}{18xy^{5}}\cdot y^{3}=-\dfrac{x^{2}}{2}$
Work Step by Step
$-\dfrac{9x^{3}y^{2}}{18xy^{5}}\cdot y^{3}$
Multiply both expressions and simplify by removing repeated factors in the numerator and the denominator:
$-\dfrac{9x^{3}y^{2}}{18xy^{5}}\cdot y^{3}=-\dfrac{9x^{3}y^{5}}{18xy^{5}}=-\dfrac{9x^{2}}{18}=-\dfrac{x^{2}}{2}$
