Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set: 7

Answer

$\dfrac{x}{2x-14}\cdot\dfrac{x^{2}-7x}{5}=\dfrac{x^{2}}{10}$

Work Step by Step

$\dfrac{x}{2x-14}\cdot\dfrac{x^{2}-7x}{5}$ Factor the denominator of the first fraction by taking out common factor $2$: $\dfrac{x}{2x-14}\cdot\dfrac{x^{2}-7x}{5}=\dfrac{x}{2(x-7)}\cdot\dfrac{x^{2}-7x}{5}=...$ Factor the numerator of the second fraction by taking out common factor $x$: $...=\dfrac{x}{2(x-7)}\cdot\dfrac{x(x-7)}{5}=...$ Multiply both rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{x^{2}(x-7)}{10(x-7)}=\dfrac{x^{2}}{10}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.