Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 499: 8

Answer

$\dfrac{4x-24}{20x}\cdot\dfrac{5}{x-6}=\dfrac{1}{x}$

Work Step by Step

$\dfrac{4x-24}{20x}\cdot\dfrac{5}{x-6}$ Factor the numerator of the first fraction by taking out common factor $4$: $\dfrac{4x-24}{20x}\cdot\dfrac{5}{x-6}=\dfrac{4(x-6)}{20x}\cdot\dfrac{5}{x-6}=...$ Multiply both rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{20(x-6)}{20x(x-6)}=\dfrac{20}{20x}=\dfrac{1}{x}$
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