Answer
$\sqrt{\dfrac{11y}{45}}=\dfrac{\sqrt{55y}}{15}$
Work Step by Step
$\sqrt{\dfrac{11y}{45}}$
Rewrite this expression as $\dfrac{\sqrt{11y}}{\sqrt{9\cdot5}}$ and simplify it:
$\sqrt{\dfrac{11y}{45}}=\dfrac{\sqrt{11y}}{\sqrt{9\cdot5}}=\dfrac{\sqrt{11y}}{3\sqrt{5}}=...$
Multiply the fraction by $\dfrac{\sqrt{5}}{\sqrt{5}}$ and simplify again:
$...=\dfrac{\sqrt{11y}}{3\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}=\dfrac{\sqrt{55y}}{3\sqrt{5^{2}}}=\dfrac{\sqrt{55y}}{3(5)}=\dfrac{\sqrt{55y}}{15}$
