Answer
$\dfrac{5}{\sqrt[3]{9}}=\dfrac{5\sqrt[3]{3}}{3}$
Work Step by Step
$\dfrac{5}{\sqrt[3]{9}}$
Multiply the fraction by $\dfrac{\sqrt[3]{9^{2}}}{\sqrt[3]{9^{2}}}$:
$\dfrac{5}{\sqrt[3]{9}}=\dfrac{5}{\sqrt[3]{9}}\cdot\dfrac{\sqrt[3]{9^{2}}}{\sqrt[3]{9^{2}}}=\dfrac{5\sqrt[3]{81}}{\sqrt[3]{9^{3}}}=\dfrac{5\sqrt[3]{81}}{9}=...$
Rewrite the expression as $\dfrac{5\sqrt[3]{27\cdot3}}{9}$ and simplify:
$...=\dfrac{5\sqrt[3]{27\cdot3}}{9}=\dfrac{5(3)\sqrt[3]{3}}{9}=\dfrac{5\sqrt[3]{3}}{3}$
