Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set: 10

Answer

$\dfrac{5}{\sqrt[3]{3y}}=\dfrac{5\sqrt[3]{9y^{2}}}{3y}$

Work Step by Step

$\dfrac{5}{\sqrt[3]{3y}}$ Multiply the fraction by $\dfrac{\sqrt[3]{9y^{2}}}{\sqrt[3]{9y^{2}}}$ and simplify: $\dfrac{5}{\sqrt[3]{3y}}=\dfrac{5}{\sqrt[3]{3y}}\cdot\dfrac{\sqrt[3]{9y^{2}}}{\sqrt[3]{9y^{2}}}=\dfrac{5\sqrt[3]{9y^{2}}}{\sqrt[3]{27y^{3}}}=\dfrac{5\sqrt[3]{9y^{2}}}{3y}$
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