Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set: 5

Answer

$\dfrac{4}{\sqrt[3]{3}}=\dfrac{4\sqrt[3]{9}}{3}$

Work Step by Step

$\dfrac{4}{\sqrt[3]{3}}$ Multiply the fraction by $\dfrac{\sqrt[3]{3^{2}}}{\sqrt[3]{3^{2}}}$ and simplify: $\dfrac{4}{\sqrt[3]{3}}=\dfrac{4}{\sqrt[3]{3}}\cdot\dfrac{\sqrt[3]{3^{2}}}{\sqrt[3]{3^{2}}}=\dfrac{4\sqrt[3]{9}}{\sqrt[3]{3^{3}}}=\dfrac{4\sqrt[3]{9}}{3}$
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