Answer
$\dfrac{2\sqrt{3}}{\sqrt{7}}=\dfrac{2\sqrt{21}}{7}$
Work Step by Step
$\dfrac{2\sqrt{3}}{\sqrt{7}}$
Multiply the fraction by $\dfrac{\sqrt{7}}{\sqrt{7}}$ and simplify:
$\dfrac{2\sqrt{3}}{\sqrt{7}}=\dfrac{2\sqrt{3}}{\sqrt{7}}\cdot\dfrac{\sqrt{7}}{\sqrt{7}}=\dfrac{2\sqrt{21}}{\sqrt{7^{2}}}=\dfrac{2\sqrt{21}}{7}$
