Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set: 15

Answer

$\dfrac{2\sqrt{3}}{\sqrt{7}}=\dfrac{2\sqrt{21}}{7}$

Work Step by Step

$\dfrac{2\sqrt{3}}{\sqrt{7}}$ Multiply the fraction by $\dfrac{\sqrt{7}}{\sqrt{7}}$ and simplify: $\dfrac{2\sqrt{3}}{\sqrt{7}}=\dfrac{2\sqrt{3}}{\sqrt{7}}\cdot\dfrac{\sqrt{7}}{\sqrt{7}}=\dfrac{2\sqrt{21}}{\sqrt{7^{2}}}=\dfrac{2\sqrt{21}}{7}$
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