Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set: 9

Answer

$\dfrac{3}{\sqrt[3]{4x^{2}}}=\dfrac{3\sqrt[3]{2x}}{2x}$

Work Step by Step

$\dfrac{3}{\sqrt[3]{4x^{2}}}$ Multiply the fraction by $\dfrac{\sqrt[3]{2x}}{\sqrt[3]{2x}}$ and simplify: $\dfrac{3}{\sqrt[3]{4x^{2}}}=\dfrac{3}{\sqrt[3]{4x^{2}}}\cdot\dfrac{\sqrt[3]{2x}}{\sqrt[3]{2x}}=\dfrac{3\sqrt[3]{2x}}{\sqrt[3]{8x^{3}}}=\dfrac{3\sqrt[3]{2x}}{2x}$
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