## Algebra: A Combined Approach (4th Edition)

$\sqrt{\dfrac{1}{2}}=\dfrac{\sqrt{2}}{2}$
$\sqrt{\dfrac{1}{2}}$ Rewrite this expression as $\dfrac{\sqrt{1}}{\sqrt{2}}$: $\sqrt{\dfrac{1}{2}}=\dfrac{\sqrt{1}}{\sqrt{2}}=\dfrac{1}{\sqrt{2}}=...$ Multiply the fraction by $\dfrac{\sqrt{2}}{\sqrt{2}}$ and simplify: $...=\dfrac{1}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{2}}{\sqrt{2^{2}}}=\dfrac{\sqrt{2}}{2}$