Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 717: 17

Answer

$\sqrt{\dfrac{2x}{5y}}=\dfrac{\sqrt{10xy}}{5y}$

Work Step by Step

$\sqrt{\dfrac{2x}{5y}}$ Rewrite the expression as $\dfrac{\sqrt{2x}}{\sqrt{5y}}$: $\sqrt{\dfrac{2x}{5y}}=\dfrac{\sqrt{2x}}{\sqrt{5y}}=...$ Multiply the fraction by $\dfrac{\sqrt{5y}}{\sqrt{5y}}$ and simplify: $...=\dfrac{\sqrt{2x}}{\sqrt{5y}}\cdot\dfrac{\sqrt{5y}}{\sqrt{5y}}=\dfrac{\sqrt{10xy}}{\sqrt{(5y)^{2}}}=\dfrac{\sqrt{10xy}}{5y}$
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