University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 296: 9.31


(a) $I = 1.93~kg~m/s$ (b) $I = 6.53~kg~m/s$ (c) I = 0 (d) $I = 1.15~kg~m/s$

Work Step by Step

Let $m_b$ be the mass of each ball and let $m_u$ be the mass of the uniform bar. (a) $I = \frac{1}{12}m_uL^2+(2\times m_br^2)$ $I = \frac{1}{12}(4.00~kg)(2.00~m)^2+2\times (0.300~kg)(1.00~m)^2$ $I = 1.93~kg~m/s$ (b) $I = \frac{1}{3}m_uL^2+0 + m_br^2$ $I = \frac{1}{3}(4.00~kg)(2.00~m)^2+(0.300~kg)(2.00~m)^2$ $I = 6.53~kg~m/s$ (c) Since the distance of all the mass from the axis of rotation is zero, $I = 0$. (d) $I = mr^2 = (4.60~kg)(0.500~m)^2$ $I = 1.15~kg~m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.