University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises: 9.30

Answer

(a) $I = \frac{mL^2}{2}$ (b) $I = \frac{11mL^2}{16}$

Work Step by Step

(a) $I = 2\times mr^2$ $I = 2\times m~(\frac{L}{2})^2$ $I = \frac{mL^2}{2}$ (b) $I = m_1~r_1^2+m_2~r_2^2+m_3~r_3^2$ $I = m~(\frac{L}{4})^2+m~(\frac{L}{4})^2+m~(\frac{3L}{4})^2$ $I = \frac{11mL^2}{16}$
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