## University Physics with Modern Physics (14th Edition)

(a) $v = 1.66~m/s$ (b) $a_{rad} = 217~m/s^2$
(a) The maximum linear speed will be a point on the edge of the drill bit. $v = (1250~rev/min)(2\pi ~r)(\frac{1~min}{60~s})$ $v = (1250~rev/min)(2\pi)(0.0127~m)(\frac{1~min}{60~s})$ $v = 1.66~m/s$ (b) The maximum radial acceleration will be at a point on the edge of the drill bit. $a_{rad} = \frac{v^2}{r} = \frac{(1.66~m/s)^2}{0.0127~m}$ $a_{rad} = 217~m/s^2$