Answer
(a) The speed of the puck is 10.8 m/s to the right.
(b) The speed of the puck is 0.75 m/s to the left.
Work Step by Step
(a) $p_2-p_1 = J$
$p_2 = F~t+p_1$
$mv_2 = F~t+ mv_1$
$v_2 = \frac{F~t+ mv_1}{m}$
$v_2 = \frac{(25.0~N)(0.050~s)+ (0.160~kg)(3.00~m/s)}{0.160~kg}$
$v_2 = 10.8~m/s$
The speed of the puck is 10.8 m/s to the right.
(b) $p_2-p_1 = J$
$p_2 = F~t+p_1$
$mv_2 = F~t+ mv_1$
$v_2 = \frac{F~t+ mv_1}{m}$
$v_2 = \frac{(-12.0~N)(0.050~s)+ (0.160~kg)(3.00~m/s)}{0.160~kg}$
$v_2 = -0.75~m/s$
The speed of the puck is 0.75 m/s to the left.
