University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 264: 8.15

Answer

The impulse imparted to the ball is $0.593~kg~m/s$.

Work Step by Step

We can find the initial velocity of the ball. $v_0^2 = v^2-2ay = 0 - 2ay$ $v_0 = \sqrt{-2ay} = \sqrt{-(2)(-9.80~m/s^2)(5.50~m)}$ $v_0 = 10.4~m/s$ We can find the impulse imparted to the ball. $J = mv = (0.0570~kg)(10.4~m/s)$ $J = 0.593~kg~m/s$ The impulse imparted to the ball is $0.593~kg~m/s$.
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