University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 264: 8.17

Answer

The momentum of the propellant gases is $0.866~kg~m/s$.

Work Step by Step

Let $p_p$ be the momentum of the propellant gases. $p_r+p_b+p_p = 0$ $p_p = -m_bv_b-m_rv_r$ $p_p = -(0.00720~kg)(601~m/s-1.85~m/s)-(2.80~kg)(-1.85~m/s)$ $p_p = 0.866~kg~m/s$ The momentum of the propellant gases is $0.866~kg~m/s$.
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