University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 8 - Momentum, Impulse, and Collision - Problems - Exercises - Page 264: 8.10

Answer

$F_x = 7050~N$ $F_y = 2150~N$

Work Step by Step

$F_x~t = \Delta p_x$ $F_x~t = m(v_{x2}-v_{x1})$ $F_x = \frac{m(v_{x2}-v_{x1})}{t}$ $F_x = \frac{(0.145~kg)[(52.0~m/s)~cos(30^{\circ})-(-40.0~m/s)]}{0.00175~s}$ $F_x = 7050~N$ $F_y~t = \Delta p_y$ $F_y~t = m(v_{y2}-v_{y1})$ $F_y = \frac{m(v_{y2}-0)}{t}$ $F_y = \frac{(0.145~kg)[(52.0~m/s)~sin(30^{\circ})]}{0.00175~s}$ $F_y = 2150~N$
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