University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 44 - Particle Physics and Cosmology - Problems - Exercises - Page 1520: 44.38

Answer

7.16 MeV. Exoergic.

Work Step by Step

The reaction energy Q is defined in equation 43.23. $Q=(M_A+M_B-M_C-M_D)c^2$. It is the mass change, converted to energy. The energy released is the mass decrease, converted to energy. The energy is $(M_{C12}+M_{He4}-M_{O16})c^2$. Using the mass values in Table 43.2, we obtain $ (7.688\times10^{-3}u)(\frac{931.5 MeV}{u})=7.16 MeV$. When Q is positive, the reaction is exoergic.
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