## University Physics with Modern Physics (14th Edition)

a. Use equation 44.14 to find the speed, with $\lambda_s=590.0 nm$, and $\lambda_o=658.5 nm$. $$v=\frac{(658.5nm/590.0nm)^2-1}{(658.5nm/590.0nm)^2+1}c=0.1094c$$ b. Using equation 44.15, the distance is $r=\frac{v}{H_o}=1.51\times10^{25}m$.