Answer
v = $1.07\times10^8\;m/s$. 1.45.
Work Step by Step
Using equation 44.15, the speed is $H_o r=(2.18\times10^{-18}s^{-1}) (4.929\times10^{25}m)=1.07\times10^8\;m/s$.
Using equation 44.13, the ratio is $\sqrt{\frac{c+v}{c-v}}$.
Plugging in numbers with $c=3.00\times10^8m/s$, the ratio is 1.45.
