Answer
7.27 MeV.
Work Step by Step
The energy released is the mass decrease, converted to energy.
The energy is $(3M_{He}-M_{C12})c^2$. Using the mass values in Table 43.2,
$(3(4.002603u)-12.00000u)c^2=(7.809\times10^{-3}u)(\frac{931.5 MeV}{u})=7.27 MeV$.
