University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1477: 43.44


See explanation.

Work Step by Step

a. Calculate the number of fissions needed. $$\frac{1.4\times10^{19}J}{(200\times10^6 eV)(1.60\times10^{-19}J/eV)}=4.38\times10^{29}$$ The mass required is $(4.38\times10^{29})(235m_p)=1.7\times10^5kg$. b. $\frac{1.7\times10^5kg }{0.007}=2.4\times10^7kg$ of mined uranium per year.
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