University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1477: 43.43


See explanation.

Work Step by Step

a. Use the atomic masses given in the problem to calculate the mass defect of 0.1860u, the total masses on the left minus the total masses on the right. This equals an energy of 173.3 MeV. b. In a gram of uranium-235, there are $\frac{0.001kg}{235m_p}=2.55\times10^{21}$ nuclei. The energy release per gram is $(173.3MeV/nucleus)(2.55\times10^{21}nuclei/g)=4.42\times10^{23}MeV/g$.
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