University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 43 - Nuclear Physics - Problems - Exercises - Page 1477: 43.39

Answer

See explanation.

Work Step by Step

a. Calculate the energy of a single photon. $E=\frac{hc}{\lambda}=\frac{(6.626\times10^{-34}J\cdot s)(3.00\times 10^8 m/s)}{0.0200\times10^{-9}m}=9.94\times10^{-15}J$ Multiply by the total number of photons to find a total energy of 0.497mJ. b. The absorbed dose is $\frac{4.97\times10^{-4}J }{0.600kg}=8.29\times10^{-4}J/kg$. This converts to 0.0828 rad. For x-rays, RBE = 1, so the equivalent dose in rem is 0.0828 rem.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.