Answer
See explanation.
Work Step by Step
The energy of the absorbed photon is given. Calculate the wavelength of the photon.
$$E= hf=h\frac{c}{\lambda} $$
$$\lambda =\frac{hc}{E}=\frac{1.24\times10^{-6}eV\cdot m}{1.01\times 10^{-5}eV}=0.1228m$$
Now find the frequency.
$$f=\frac{c}{\lambda}$$
$$f =\frac{3.00\times10^{8}m/s }{0.1228m}=2.44\times10^{9}Hz$$
This makes sense as it is very close to 2450 MHz, the frequency given for a microwave oven.
